Change the chapter
Question
What depth of mercury creates a pressure of 1.00 atm?
Question by OpenStax is licensed under CC BY 4.0.
$0.760 \textrm{ m}$
Solution Video

OpenStax College Physics for AP® Courses Solution, Chapter 11, Problem 14 (Problems & Exercises) (1:26)

Sign up to view this solution video!

Rating

No votes have been submitted yet.

Quiz Mode

Why is this button here? Quiz Mode is a chance to try solving the problem first on your own before viewing the solution. One of the following will probably happen:

  1. You get the answer. Congratulations! It feels good! There might still be more to learn, and you might enjoy comparing your problem solving approach to the best practices demonstrated in the solution video.
  2. You don't get the answer. This is OK! In fact it's awesome, despite the difficult feelings you might have about it. When you don't get the answer, your mind is ready for learning. Think about how much you really want the solution! Your mind will gobble it up when it sees it. Attempting the problem is like trying to assemble the pieces of a puzzle. If you don't get the answer, the gaps in the puzzle are questions that are ready and searching to be filled. This is an active process, where your mind is turned on - learning will happen!
If you wish to show the answer immediately without having to click "Reveal Answer", you may . Quiz Mode is disabled by default, but you can check the Enable Quiz Mode checkbox when editing your profile to re-enable it any time you want. College Physics Answers cares a lot about academic integrity. Quiz Mode is encouragement to use the solutions in a way that is most beneficial for your learning.

Calculator Screenshots

OpenStax College Physics, Chapter 11, Problem 14 (PE) calculator screenshot 1
Video Transcript
This is College Physics Answers with Shaun Dychko. Given the pressure exerted by a column of mercury of 1 atmosphere, we are gonna figure out what the height of that column of mercury is. So we know that the pressure equals that height times the mercury's density times gravitational field strength and we can solve this for h by dividing by ρg on both sides and we get that h is the pressure divided by density times gravitational field strength. So the one thing to be mindful of in this question is units. So we are given 1 atmosphere for the pressure but we have to convert that into pascals by multiplying by 1.013 times 10 to the 5 pascals per atmosphere and then the density for mercury we can look up in table [11.1] but we have two choices: we can say 13.6 grams per milliliter or we can say 13.6 times 10 to the 3 kilograms per cubic meter and it's the kilograms per cubic meter version that we are gonna choose here because we want mks units in a formula here that involves pascals because pascals are really newtons per square meter and so we need meters in this density here. Okay! So we have 1.013 times 10 to the 5 pascals divided by 13.6 times 10 to the 3 kilograms per cubic meter times 9.80 newtons per kilogram giving a height of 0.760 meters.