Question

What is the separation between two slits for which 610-nm orange light has its first maximum at an angle of $30.0^\circ$?

$1.22 \textrm{ }\mu\textrm{m}$

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This is College Physics Answers with Shaun Dychko. During a double slit experiment, we are using light of wavelength 610 nanometers and the first maximum occurs at a angle of 30.0 degrees so

*m*in this formula here for the locations of the constructive interference or the maxima*m*is going to be 1 because it's the first maximum,*d*is the separation between the slits that we have to find. So we are going to divide both sides by*sin*of 30 and that gives us*d*equals the order times the wavelength of light divided by*sin*of the angle to the maximum... I suppose I should put a*Θ*there. Okay! So the order is 1 because it's the first maximum and we multiply that by 610 nanometers divided by*sin*of 30 and that's 1220 nanometers, which is 1.22 micrometers.