Question
(b)
This is College Physics Answers with Shaun Dychko. A dark fringe means you have destructive interference. And so, when you have a wave with a higher amplitude used in the second iteration of this experiment, you expect the destructive interference to be just the same. So, intensity of the dark fringe is kind of a contradiction of terms because, well, it's like saying the amount of zero will be different. You can't have zero being any different than zero any other time. This darkness means zero amplitude of the super positioned waves at a certain point where there's the dark fringe. So anyway, the darkness of the dark fringe will not change. And so, the answer here is B.
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