Question

If you have completely polarized light of intensity $150\textrm{ W/m}^2$ , what will its intensity be after passing through
a polarizing filter with its axis at an $89.0^\circ$ angle to the light’s polarization direction?

$4.57\times 10^{-2}\textrm{ W/m}^2$

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Video Transcript

This is College Physics Answers with Shaun Dychko. Polarized light with an intensity of 150 watts per square meter is going to be going through a polarizing filter that has its axis at an angle of 89.0 degrees to the direction of the lights polarization. So the intensity then is going to be this initial intensity going into the polarizing filter times

*cosine*of this angle squared. So that's 150 watts per square meter times*cos*of 89.0 degrees and then square that and we get 4.57 times 10 to the minus 2 watts per square meter will be the intensity that has passed through the polarizing filter.