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Question
Prove that, if $I$ is the intensity of light transmitted by two polarizing filters with axes at an angle $\theta$ and $I'$ is the intensity when the axes are at an angle $90.0^\circ - \theta$, then $I + I' = I_0$, the original intensity. (Hint: Use the trigonometric identities $\cos{(90.0^\circ - \theta)} = \sin{\theta}$ and $\cos ^2 \theta + \sin ^2 \theta = 1$.)
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