Question
Suppose a particle called a kaon is created by cosmic radiation striking the atmosphere. It moves by you at 0.980c0.980c, and it lives 1.24×108 s1.24\times 10^{-8}\textrm{ s} when at rest relative to an observer. How long does it live as you observe it?
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Final Answer

6.23×108 s6.23\times 10^{-8}\textrm{ s}

Solution video

OpenStax College Physics, Chapter 28, Problem 4 (Problems & Exercises)

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Video Transcript
This is College Physics Answers with Shaun Dychko. A kaon particle is moving at 0.980 times the speed of light c; when an observer is at rest with respect to the particle, they measure a lifetime for it of 1.24 times 10 to the minus 8 seconds and because this time is measured at rest with respect to the particle, it's called the proper time, t naught. So Δt—the time measured by the person watching the things zip by— equals the Lorentz factor γ times the proper time. So that's 1 over the square root of 1 minus v squared over c squared times Δt naught and that's 1 over the square root of 1 minus 0.980 times c all squared over c squared times 1.24 times 10 to the minus 8 seconds and that is 6.23 times 10 to the minus 8 seconds. This is the time measured by an Earth-based observer watching the kaon particle zip past.