Question

To receive AM radio, you want an RLC circuit that can be made to resonate at any frequency between 500 and 1650 kHz. This is accomplished with a fixed $1.00\textrm{ }\mu\textrm{H}$ inductor connected to a variable capacitor. What range of capacitance is needed?

Final Answer

$9.30\textrm{ nF} \le \textrm{C} \le 101\textrm{ nF}$

### Solution video

# OpenStax College Physics for AP® Courses, Chapter 23, Problem 96 (Problems & Exercises)

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Video Transcript

This is College Physics Answers with Shaun Dychko. An AM radio needs its

*LRC*-circuit to resonate from a minimum frequency of 500 kilohertz upto a maximum frequency of 1650 kilohertz and it has an inductor in it with an inductance of 1.00 microhenries. So we need to figure out what capacitance is needed in order to resonate at each of these frequencies? So the resonant frequency of an*LRC*-circuit is 1 over 2*π*times the square root of the product of the inductance and capacitance and we can solve this for*C*by first squaring both sides and we have*f naught squared*on the left equals 1 over 4*π squaredLC*on the right and then multiply both sides by*C*over*f naught squared*. So the capacitance then is 1 over 4*π squared*times inductance times the resonant frequency squared. So the first capacitance will be 1 over 4*π squared*times inductance times the minimum resonant frequency squared so that's 1 over 4*π squared*times 1.00 times 10 to the minus 6 henries times 500 times 10 to the 3 hertz squared which is 101 nanofarads. The second capacitance needed is 1 over 4*π squared*times the inductance times the maximum frequency— 1650 times 10 to the 3 hertz squared— and that is 9.30 nanofarads. So the capacitance needs to be variable from a minimum of 9.30 nanofarads upto 101 nanofarads.