Question

When tightening a bolt, you push perpendicularly on a wrench with a force of 165 N at a distance of 0.140 m from the center of the bolt. (a) How much torque are you exerting in newton × meters (relative to the center of the bolt)? (b) Convert this torque to footpounds.

- $23.1 \textrm{ N}\cdot\textrm{m}$
- $17.0 \textrm{ ft}\cdot\textrm{lbs}$

**Note:** The video incorrectly shows the conversion to $\textrm{ft}\cdot\textrm{lbs}$ by dividing instead of multiplying by 0.7356. The calculator screenshot has been corrected, and the final answer above is correct.

Solution Video

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## Calculator Screenshots

Video Transcript

This is College Physics Answers with Shaun Dychko. We are going to calculate the torque applied about the bolt when applying a force of 165 newtons on the wrench at a distance that's perpendicular to the pivot, 0.140 meters away. So we multiply these two together and get 23.1 newton meters and converting that into foot pounds by multiplying by 1 ft lbs for every 0.73756 newton meters, this is 31.3 ft lbs.