This is College Physics Answers with Shaun Dychko. A rugby player is initially going 8.00 meters per second to the right in this picture and they collide with a padded goal post which exerts a force backwards on the rugby player, we'll call that <i>F P</i> for 'post'. And we are told that that force is 1.76 times 10 to the 4 newtons and the mass of the rugby player is 110 kilograms and this post force is applied for 5.50 times 10 to the minus 2 seconds. And I have labeled this initial velocity <i>v</i> and the final velocity that we want to find is <i>v prime</i>. Okay! So the change in momentum of the rugby player will be the net force on them multiplied by time—this is the impulse formula— and you could also write the change in momentum as the final momentum minus the initial momentum where we have mass times final velocity minus mass times initial velocity here. So since both of these equal the change in momentum, we can make them equal to each other which we do in this line here so <i>mv prime</i> minus <i>mv</i> equals <i>F net</i> times <i>t</i>. And then we substitute the force exerted by the post in place of the net force because this is the only horizontal force in this picture and so that is the net horizontal force; we can ignore gravity and normal force because they are vertical and independent. So we add <i>mv</i> to this side and to this side to isolate <i>mv prime</i> here on the left— <i>mv prime</i> equals <i>F P t</i> plus <i>mv</i>— and then divide both sides by the mass and we get a formula for the final velocity. So that's the force exerted by the post multiplied by time plus mass times initial velocity all divided by mass. So that's negative 1.76 times 10 to the 4 newtons times 5.50 times 10 to the minus 2 seconds plus 110 kilograms times 8.00 meters per second divided by 110 kilograms making a final velocity of negative 0.800 meters per second. The negative sign indicates that the rugby player is bouncing off this post and they will be going to the left in this picture after the collision.