Question

A 5.50-kg bowling ball moving at 9.00 m/s collides with a 0.850-kg bowling pin, which is scattered at an angle of $85.0^\circ$ to the initial direction of the bowling ball and with a speed of 15.0 m/s. (a) Calculate the final velocity (magnitude and direction) of the bowling ball. (b) Is the collision elastic? (c) Linear kinetic energy is greater after the collision. Discuss how spin on the ball might be converted to linear kinetic energy in the collision.

Final Answer

- $9.10 \textrm{ m/s, }14.7^\circ \textrm{ above horizontal}$
- The collision is not elastic.
- Immediately after collision the ball will be rotating such that a point on the edge of the ball will be moving faster than it's briefly arrested linear velocity. This will cause slipping that will linearly accelerate the ball, resulting in the conversion of rotational kinetic energy into linear kinetic energy.

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