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Question
(a) What is the direction and magnitude of an electric field that supports the weight of a free electron near the surface of Earth? (b) Discuss what the small value for this field implies regarding the relative strength of the gravitational and electrostatic forces.
1. $5.59\times 10^{-11}\textrm{ N/C}$
2. The electrostatic force is much greater than gravity since a much smaller electric field is needed to create the same magnitude force as gravity.
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