What current flows through the bulb of a 3.00-V flashlight when its hot resistance is $3.60\text{Omega}$?

Video Transcript

This is College Physics Answers with Shaun Dychko. We want to know what the current is through a 3.60 ohm bulb in a flashlight that operates at 3.00 volts. So the voltage is current multiplied by resistance and so we can solve for the current by dividing both sides by R then we get that I is V over R. So that's 3.00 volts divided by 3.60 ohms, which is 0.833 amps.