Question
A certain circuit breaker trips when the rms current is 15.0 A. What is the corresponding peak current?
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This is College Physics Answers with Shaun Dychko. A certain circuit breaker will trip when the rms current is 15.0 amps and we are asked what would the peak current be when the I rms is 15? So the formula for I rms is peak current divided by square root of 2 so I multiply both sides by square root 2 to solve for I naught. So the peak current then is square root 2 times I rms so that's square root 2 times 15.0 amps which is 21.2 amps.
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