Calculate the effective resistance of a pocket calculator that has a 1.35-V battery and through which 0.200 mA flows.

Name: Calculate the effective resistance of a pocket calculator that has a… | College Physics Answers
Uploaded: 2018-04-26T23:39:22.000Z
Duration: 21 s
Description: Calculate the effective resistance of a pocket calculator that has a 1.35-V battery and through which 0.200 mA flows.

Question by OpenStax is licensed under CC BY 4.0

Final Answer

6750 \textrm{ } \Omega

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Video Transcript

This is College Physics Answers with Shaun Dychko. The pocket calculator has a 1.35 volt battery and the current flowing through it is 0.2 times ten to the minus three amps. So resistance is voltage divided by current, so 1.35 volts divided by 0.2 times ten to the minus three amps gives us 6750 ohms.