Question
Find the direction and magnitude of the force that each wire experiences in Figure 22.58(b), using vector addition.
Question Image

$\dfrac{F_A}{l} = 1.06 \times 10^{-4} \textrm{ N/m, } 45.0^\circ \textrm{ above positive x-axis}$

$\dfrac{F_B}{l} = 1.06 \times 10^{-4} \textrm{ N/m, } 45.0^\circ \textrm{ above negative x-axis}$

$\dfrac{F_C}{l} = 7.50 \times 10^{-5} \textrm{ N/m straight down}$

$\dfrac{F_D}{l} = 7.50 \times 10^{-5} \textrm{ N/m straight down}$

Solution Video