$18.3 \textrm{ MHz}$

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This is College Physics Answers with Shaun Dychko. The previous question has a formula telling us what the period of orbit will be for a particle in the cyclotron, it will be <i>2 pi</i> times its mass divided by the charge times the magnetic field strength of the cyclotron. Now frequency is the reciprocal of period and so we’ll take this to the power of negative one and say frequency is <i>qB</i> over <i>2 pi m</i>. And that means it’s 1.6 times ten to the minus 19 coulomb, because that’s the charge on a proton, times 1.2 Tesla which we’re told in the question is the magnetic field strength, divided by two times <i>pi</i> times the mass of a proton, 1.67 times ten to the minus 27 kilograms, giving us 18.3 mega-Hertz is the frequency of this accelerating voltage.