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What voltage must be applied to an 8.00 nF capacitor to store 0.160 mC of charge?
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$20.0\textrm{ kV}$
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OpenStax College Physics Solution, Chapter 19, Problem 50 (Problems & Exercises) (0:46)

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Video Transcript
This is College Physics Answers with Shaun Dychko. What voltage is needed to store 0.160 millicoulombs on an 8.00 nanofarad capacitor? So I have expressed these quantities without prefixes so the 'nano' becomes times 10 to the minus 9 and the 'milli' becomes 10 to the minus 3 and then we look at our formula here which says capacitance is charge divided by voltage and we can solve for V by multiplying both sides by V over C and this leaves us with the voltage is the charge divided by the capacitance. So that's 0.160 times 10 to the minus 3 coulombs divided by 8.00 times 10 to the minus 9 farads which is 20.0 kilovolts.