What voltage must be applied to an 8.00 nF capacitor to store 0.160 mC of charge?
This is College Physics Answers with Shaun Dychko. What voltage is needed to store 0.160 millicoulombs on an 8.00 nanofarad capacitor? So I have expressed these quantities without prefixes so the 'nano' becomes times 10 to the minus 9 and the 'milli' becomes 10 to the minus 3 and then we look at our formula here which says capacitance is charge divided by voltage and we can solve for V by multiplying both sides by V over C and this leaves us with the voltage is the charge divided by the capacitance. So that's 0.160 times 10 to the minus 3 coulombs divided by 8.00 times 10 to the minus 9 farads which is 20.0 kilovolts.