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What capacitance is needed to store $3.00 \textrm{ }\mu\textrm{C}$ of charge at a voltage of 120 V?
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$25.0 \textrm{ nF}$

Solution Video

OpenStax College Physics Solution, Chapter 19, Problem 51 (Problems & Exercises) (0:22)

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Video Transcript
This is College Physics Answers with Shaun Dychko. The capacitance needed to store three microCoulombs of charge when 120 volts is applied can be found by taking the charge divided by the voltage. So, that's three times ten to the minus six Coulombs divided by 120 volts is 25.0 nanofarads.


Submitted by goblinking88 on Thu, 02/25/2021 - 13:41

would is be 2.5x10^-8 F if you were to leave it in scientific notation