What capacitance is needed to store 3.00 μC3.00 \textrm{ }\mu\textrm{C} of charge at a voltage of 120 V?
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Final Answer

25.0 nF25.0 \textrm{ nF}

Solution video

OpenStax College Physics, Chapter 19, Problem 51 (Problems & Exercises)

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Video Transcript
This is College Physics Answers with Shaun Dychko. The capacitance needed to store three microCoulombs of charge when 120 volts is applied can be found by taking the charge divided by the voltage. So, that's three times ten to the minus six Coulombs divided by 120 volts is 25.0 nanofarads.


would is be 2.5x10^-8 F if you were to leave it in scientific notation