Question
The electric field strength between two parallel conducting plates separated by 4.00 cm is $7.50 \times 10^4 \textrm{ V/m}$. (a) What is the potential difference between the plates? (b) The plate with the lowest potential is taken to be at zero volts. What is the potential 1.00 cm from that plate (and 3.00 cm from the other)?
1. $3.00 \times 10^3 \textrm{ V}$
2. $750 \textrm{ V}$
Solution Video