Find the total capacitance of the combination of capacitors in Figure 19.32.
<b>Figure 19.32</b> A combination of series and parallel connections of capacitors.
Figure 19.32 A combination of series and parallel connections of capacitors.
Question by OpenStax is licensed under CC BY 4.0
Final Answer

0.29 μF0.29 \textrm{ }\mu\textrm{F}

Solution video

OpenStax College Physics, Chapter 19, Problem 57 (Problems & Exercises)

OpenStax College Physics Answers, Chapter 19, Problem 57 video poster image.

In order to watch this solution you need to have a subscription.

Start free trial Log in
vote with a rating of votes with an average rating of .

Calculator Screenshots

  • OpenStax College Physics, Chapter 19, Problem 57 (PE) calculator screenshot 1
Video Transcript
This is College Physics Answers with Shaun Dychko. We're going to find the equivalent capacitance of this circuit, and we'll do it step by step. And, the first step is to combine these two capacitors in parallel and write an equivalent capacitance in this new schematic here. And so, I've copied the 0.03 microfarads unchanged here. And here, I've written capacitance equivalent number one. And, that's going to be the arithmetic sum of these two capacitances because when the capacitors are parallel, as these two are, you add the capacitances directly to get the equivalent capacitance. So, Ceq1 is 12 and a half microfarads. Then, we're going to combine this Ceq1 with the 0.30 microfarads and to do that, we take the reciprocal of each one and add, and then take the reciprocal of that sum. And so, this exponent negative one means take the reciprocal of the result in here. So we have one over 12.5 microfarads plus one over 0.30 microfarads. And then, take the reciprocal of that sum, and we end up with 0.29 microfarads with the equivalent capacitance in total.


I too got this answer after trying 2.3 micro Farads and the homework said both were wrong. I don't know what's wrong with it it seems right to me.

Hello, I'm not sure where you're getting 2.3 μF2.3\textrm{ }\mu\textrm{F} from? In any case, I have double checked the solution here, and it looks correct. Perhaps your online homework system is using different values for the capacitances?
All the best,