Question
In Figure 4.7, the net external force on the 24-kg mower is stated to be 51 N. If the force of friction opposing the motion is 24 N, what force (in newtons) is the person exerting on the mower? Suppose the mower is moving at 1.5 m/s when the force is removed. How far will the mower go before stopping?
Question Image

$F_p = 75 \textrm{ N}$

$x = 1.1 \textrm{ m}$

Solution Video

# OpenStax College Physics Solution, Chapter 4, Problem 5 (Problems & Exercises) (3:48)

$x^2$ or $\dfrac{a^2}{b^2}$