Question
Prove that, to three-digit accuracy, h=4.14×1015 eVsh = 4.14 \times 10^{-15} \textrm{ eV}\cdot \textrm{s}, as stated in the text.
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OpenStax College Physics, Chapter 29, Problem 27 (Problems & Exercises)

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Video Transcript
This is College Physics Answers with Shaun Dychko. We can show that Planck's constant written in units of joules seconds is 4.14 times 10 to the minus 15 electron volt seconds by multiplying Planck's constant by 1 electron volt for every 1.602 times 10 to the minus 19 joules and there we go.