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Question
Prove that, to three-digit accuracy, $h = 4.14 \times 10^{-15} \textrm{ eV}\cdot \textrm{s}$, as stated in the text.
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Solution Video

OpenStax College Physics Solution, Chapter 29, Problem 27 (Problems & Exercises) (0:22)

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This is College Physics Answers with Shaun Dychko. We can show that Planck's constant written in units of joules seconds is 4.14 times 10 to the minus 15 electron volt seconds by multiplying Planck's constant by 1 electron volt for every 1.602 times 10 to the minus 19 joules and there we go.