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Question
Naturally occurring ${}^{40}\textrm{K}$ is listed as responsible for 16 mrem/y of background radiation. Calculate the mass of ${}^{40}\textrm{K}$ that must be inside the 55-kg body of a woman to produce this dose. Each ${}^{40}\textrm{K}$ decay emits a 1.32-MeV $\beta$ , and 50% of the energy is absorbed inside the body.
$1.02\times 10^{-2}\textrm{ g}$
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