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Question
(a) Calculate the energy released in the neutron-induced fission (similar to the spontaneous fission in Example 32.3 where
$n + {}^{238}\textrm{U} \to {}^{96}\textrm{Sr} + {}^{140}\textrm{Xe} + 3n$
given that $m({}^{96}\textrm{Sr} = 95.921750 \textrm{ u}$ and $m({}^{140}\textrm{Xe} = 139.92164 \textrm{ u}$. (b) This result is about 6 MeV greater than the result for spontaneous fission. Why? (c) Confirm that the total number of nucleons and total charge are conserved in this reaction.
1. $177.0 \textrm{ MeV}$
2. The 6 MeV gain is due to the additional incident neutron.
3. Please see the solution video.
Solution Video