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Question
Neutrons from a source (perhaps the one discussed in the x-ray series) bombard natural molybdenum, which is 24 percent ${}^{98}\textrm{Mo}$. What is the energy output of the reaction ${}^{98}\textrm{Mo} + n \rightarrow {}^{99}\textrm{Mo} + \gamma$? The mass of ${}^{98}\textrm{Mo}$ is given in Appendix A: Atomic Masses, and that of ${}^{99}\textrm{Mo}$ is 98.907711 u.
$5.924\textrm{ MeV}$
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