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Question
The annual radiation dose from ${}^{14}\textrm{C}$ in our bodies is 0.01 mSv/y. Each ${}^{14}\textrm{C}$ decay emits a $\beta^-$ averaging 0.0750 MeV. Taking the fraction of ${}^{14}\textrm{C}$ to be $1.3\times 10^{-12}$ of normal ${}^{12}\textrm{C}$, and assuming the body is 13% carbon, estimate the fraction of the decay energy absorbed. (The rest escapes, exposing those close to you.)
$0.947$
Solution Video