Question
(a) Calculate BE / A for $^{12}\textrm{C}$. Stable and relatively tightly bound, this nuclide is most of natural carbon. (b) Calculate BE / A for $^{14}\textrm{C}$. Is the difference in BE / A between $^{12}\textrm{C}$ and $^{14}\textrm{C}$ significant? One is stable and common, and the other is unstable and rare.
1. $7.680\textrm{ MeV/nucleon}$
2. $7.520\textrm{ MeV/nucleon}$

A 2.1% difference is sufficient to make $^{14}\textrm{C}$ tend to decay into more tightly bound nuclides.

Solution Video