Question
$^2\textrm{H}$ is a loosely bound isotope of hydrogen. Called deuterium or heavy hydrogen, it is stable but relatively rare—it is 0.015% of natural hydrogen. Note that deuterium has Z = N , which should tend to make it more tightly bound, but both are odd numbers. Calculate BE/A , the binding energy per nucleon, for $^2H$ and compare it with the approximate value obtained from the graph in Figure 31.27.
$1.112 \textrm{ MeV/nucleon}$
This matches that shown on Figure 31.27.
Solution Video