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Question
At takeoff, a commercial jet has a 60.0 m/s speed. Its tires have a diameter of 0.850 m. (a) At how many rev/min are the tires rotating? (b) What is the centripetal acceleration at the edge of the tire? (c) With what force must a determined $1.00 \times 10^{-15}\textrm{ kg}$ bacterium cling to the rim? (d) Take the ratio of this force to the bacterium's weight.
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Final Answer
  1. $1350 \textrm{ rev/min}$
  2. $8.47 \times 10^{3}\textrm{ m/s}^2$
  3. $8.47 \textrm{ -12} \textrm{ N}$
  4. $864$
Solution Video

OpenStax College Physics Solution, Chapter 6, Problem 20 (Problems & Exercises) (2:28)

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