Question

In lacrosse, a ball is thrown from a net on the end of a stick by rotating the stick and forearm about the elbow. If the angular velocity of the ball about the elbow joint is 30.0 rad/s and the ball is 1.30 m from the elbow joint, what is the velocity of the ball?

Final Answer

$39.0 \textrm{ m/s}$

### Solution video

# OpenStax College Physics for AP® Courses, Chapter 6, Problem 6 (Problems & Exercises)

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Video Transcript

This is College Physics Answers with Shaun Dychko. The ball on the end of a lacrosse stick is traveling with an angular speed of 30.0 radians per second and this ball is positioned 1.30 meters from the pivot which is the elbow joint. So the linear speed of the ball then is that distance from the pivot to the ball times by the angular speed. So this is 1.30 meters times 30.0 radians per second which is 39.0 meters per second.