Question
Twin skaters approach one another as shown in Figure 10.39 and lock hands. (a) Calculate their final angular velocity, given each had an initial speed of 2.50 m/s relative to the ice. Each has a mass of 70.0 kg, and each has a center of mass located 0.800 m from their locked hands. You may approximate their moments of inertia to be that of point masses at this radius. (b) Compare the initial kinetic energy and final kinetic energy.
Question Image

a) $3.13 \textrm{ rad/s}$

b) $KE = 438 \textrm{ J}$

$KE' = 438 \textrm{ J}$

The kinetic energy is the same before and after they join hands.

Solution Video