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Estimate the density of a nucleus by calculating the density of a proton, taking it to be a sphere 1.2 fm in diameter. Compare your result with the value estimated in this chapter.
Question by OpenStax is licensed under CC BY 4.0.
$1.8\times 10^{18}\textrm{ kg/m}^3$
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OpenStax College Physics for AP® Courses Solution, Chapter 30, Problem 51 (Problems & Exercises) (1:04)

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Video Transcript

This is College Physics Answers with Shaun Dychko. We are going to calculate the density of a proton assuming it has a diameter of 1.2 femtometers. So density is mass divided by volume and we'll take the proton to be a sphere in which case the volume is four-thirds <i>π</i> times radius cubed and then multiply top and bottom by 3; these 3's cancel leaving us a 3 on top. So we have 3<i>m</i> over 4<i>π</i> times radius cubed but we'll write radius as diameter divided by 2 since we are given diameter and we'll cube that and in which case, we have a denominator of 8 because 2 cubed is 8 and 4 with that 8 in the denominator there makes a denominator of 2 underneath <i>d</i> cubed and multiply top and bottom by 2, we end up with 6<i>m</i> over <i>π d</i> cubed. So the density then is 6 times the mass of a proton divided by <i>π</i> times the diameter of a proton cubed which is 1.8 times 10 to the 18 kilograms per cubic meter.