Question

Verify the second equation in Example 21.5 by substituting the values found for the currents $I_1$ and $I_2$.

The equation is $-3I_2 + 18 - 6I_1 = 0$. $I_1 = 4.75 \textrm{ A}$, $I_2 = -3.50 \textrm{ A}$.

Final Answer

Yes, the equation equals zero, as expected.

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This is College Physics Answers with Shaun Dychko.
The equation we are given in the example is negative three times current two plus 18 minus six times current one equals zero. And current one, the example solves 4.75 Amps and current two is negative 3.5 Amps. And so we substitute this number in for

*I2*and*I1*and we end showing that this does indeed equals zero. So we verified the equation.