Question
The hot resistance of a flashlight bulb is $2.30 \Omega$ , and it is run by a 1.58-V alkaline cell having a $0.100 \Omega$ internal resistance. (a) What current flows? (b) Calculate the power supplied to the bulb using $I^2R_{bulb}$. (c) Is this power the same as calculated using $\dfrac{V^2}{R}$?
1. $0.658 \textrm{ A}$
2. $0.997 \textrm{ W}$
3. Yes, $\dfrac{V^2}{R}$ gives the same answer.
Solution Video