- $-400 \textrm{ k}\Omega$
- Resistance can't be negative
- Either $R_1$ is too large, or $R_s$ is too small. $R_s$ is always more than any of the component resistors in series.

#### Sign up to view this solution video!

## Calculator Screenshots

This is College Physics Answers with Shaun Dychko. We are told that two resistors are connected in series and we have to solve for <i>R2</i>. And so we’ll subtract <i>R1</i> from both sides and we get <i>R2</i> is the total resistance in series minus <i>R1</i>. So that’s 0.5 Mega Ohms. Mega is the prefix meaning multiplied by ten to the six. And then we have minus 900 kilo Ohms. Kilo is the metric prefix meaning multiplied by ten to the three. And so this works out to negative 400 kilo Ohms. And that’s not reasonable because resistances can’t be negative. And so either <i>R1</i> is too large and so we shouldn’t be subtracting so much away from this total. And it might look like this number is smaller than this one because this is only ten to the three whereas this is ten to the six. I haven’t technically written this in scientific notation. For scientific notation would say: it would say don’t have these zeros that’s for sure. And one number to the left of the decimals, so this would be 5.00 times ten to the five. And this would be 9.00 times ten to the five. Now it’s easier to compare because they have the same multiplier here. And so this clearly is bigger and with that we can compare the nine to the five and nine is bigger than five. So, either <i>R1</i> is been given to us as a number that is mistakenly too large. Or the series resistance that we’re given is too small. Maybe this number should in fact be much bigger, because the total resistance of two resistors in series is always more than any one of the particular resistors.