- see solution video for drawing
- Yes, the resulting field is smaller near the long side.
This is College Physics Answers with Shaun Dychko. Initially we have an electric field of parallel lines pointing to the right side, and afterwards we introduce this conducting object into that field. And what it’s going to do is the field will result in charge distribution in this conductor. We can think of electric field lines as pointing in the direction of the force that would be applied on a positive charge, so you can think of it as pushing positive charges away to the right hand side, although we know that positive charges are in the nucleus so they don’t actually move. And so instead what happens is negative charges are attracted towards this end here. So we have negative charges on this end, positive charges on this end, and so these field lines are going to stop on the object. And then sort of continue from the other side, and this is resulting in fewer field lines on the long side of this object. So the answer to part b is the resulting field is going to be smaller here because we see only one field line near this location here whereas before there were two field lines you could say. But this field line has now been intercepted and then reemerged you might say from the other side. There we go.
Submitted by kmcmullen on Wed, 01/23/2019 - 14:34
a) How strong is the attractive force between a glass rod
with a 0.700 μC charge and a silk cloth with a –0.600 μC
charge, which are 12.0 cm apart, using the approximation that
they act like point charges? (b) Discuss how the answer to
this problem might be affected if the charges are distributed
over some area and do not act like point charges.
Submitted by ShaunDychko on Thu, 01/24/2019 - 10:00
All the best,
Submitted by masonflanagan on Tue, 07/02/2019 - 23:05