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Calculate the magnitude of the electric field 2.00 m from a point charge of 5.00 mC (such as found on the terminal of a Van de Graaff).
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Final Answer

$1.12 \times 10^7 \textrm{ N/C}$

Solution Video

OpenStax College Physics Solution, Chapter 18, Problem 29 (Problems & Exercises) (0:30)

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Video Transcript

This is College Physics Answers with Shaun Dychko. We're going to calculate the magnitude of the electric field two meters away from a charge of five milli Coulombs which is five times ten to the minus three Coulombs. The electric field Coulombs Constant times <i>q</i> over <i>r</i> squared. So that's 8.988 times ten to the nine Newtons meter squared per Coulombs squared times five times ten to the minus three Coulombs divided by two meters squared giving 1.12 times ten to the seven Newtons per Coulomb is the electric field strength.