A thermodynamic process begins at $1.2\times 10^6{\text{ N/m}}^2$ and 5 L. The state then changes to $1.2\times 10^6{\text{ N/m}}^2$ and 2 L. Next it becomes $2.2\times 10^6{\text{ N/m}}^2$ and 2 L. The next change is $2.2\times 10^6{\text{ N/m}}^2$ and 5 L. Finally, the system ends at $1.0\times 10^6{\text{ N/m}}^2$ and 5 L.

Video Transcript

This is College Physics Answers with Shaun Dychko. A thermodynamic process begins at 1.2 times 10 to the 6 newtons per square meter in pressure and 5 liters. And so that's going to be this point here and the state then changes to the same pressure and so it’s going to go horizontally but to a smaller volume to 2 liters. So this is 2 liters and this is 5 liters and then it stays at 2 liters and increases its pressure to 2.2 times 10 to the 6 newtons per square meter. So let’s label this as 1.2 times 10 to the 6 and up here it's gonna be 2.2 times 10 to the 6. So moves up to here and then it goes at the same pressure 2.2, it goes to 5 liters and so it moved here and then finally it ends at 1 point 0 times 10 to the 6 newtons per square meter but staying at 5 liters and so it passes point C because point C was 1.2 times 10 to the 6 and it ends at 1 point 0 times 10 to the 6 newtons per square meter. There we go, the answer is D, CFABD