Question
Suppose two children are using a uniform seesaw that is 3.00 m long and has its center of mass over the pivot. The first child has a mass of 30.0 kg and sits 1.40 m from the pivot. (a) Calculate where the second 18.0 kg child must sit to balance the seesaw. (b) What is unreasonable about the result? (c) Which premise is unreasonable, or which premises are inconsistent?

a) $2.33 \textrm{ m}$

b) Child two is past the end of the seesaw!

c) The first child must be moved closer to the pivot.

Solution Video