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Question
Suppose a man stands in front of a mirror as shown in Figure 25.50. His eyes are 1.65 m above the floor, and the top of his head is 0.13 m higher. Find the height above the floor of the top and bottom of the smallest mirror in which he can see both the top of his head and his feet. How is this distance related to the man’s height?
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$h_\textrm{b} = 0.825 \textrm{ m}$
$h_\textrm{t} = 1.72 \textrm{ m}$
Note: The man's height affects the answer: the height of the bottom of the mirror is half the distance from the man's eyes and the ground, whereas the top of the mirror height is the height of the man's eyes plus half the distance between the man's eyes and top of his head.
Solution Video

# OpenStax College Physics Solution, Chapter 25, Problem 1 (Problems & Exercises) (2:43)

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Submitted by ryanzurrin on Mon, 04/12/2021 - 04:24

the length of the mirror is related to the height of a person by just being half of their height. Will this be true in all cases though?

Submitted by be1988 on Wed, 05/19/2021 - 22:36

This doesn't answer the last part of the question, "How is this distance related to the man’s height?"

Submitted by ryanzurrin on Sat, 05/22/2021 - 18:58

Using ray-tracing and the law of reflection, the angle of incidence is equal to the angle of reflection, so the top of the mirror has to extend to at least halfway between their eyes and the top of their head. The bottom must go down to halfway between their eyes and the floor. This result is independent of how far they are standing from the wall.