Question

Suppose a man stands in front of a mirror as shown in Figure 25.50. His eyes are 1.65 m above the floor, and the top of his head is 0.13 m higher. Find the height above the floor of the top and bottom of the smallest mirror in which he can see both the top of his head and his feet. How is this distance related to the man’s height?

<b>Figure 25.50</b> A full-length mirror is one in which you can see all of yourself. It need not be as big as you, and its size is independent of your distance from it. — **Figure 25.50** A full-length mirror is one in which you can see all of yourself. It need not be as big as you, and its size is independent of your distance from it.

Question by OpenStax is licensed under CC BY 4.0.

Final Answer

$h_\textrm{b} = 0.825 \textrm{ m}$
$h_\textrm{t} = 1.72 \textrm{ m}$

Solution Video

OpenStax College Physics Solution, Chapter 25, Problem 1 (Problems & Exercises) (2:43)

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Calculator Screenshots

OpenStax College Physics, Chapter 25, Problem 1 (PE) calculator screenshot 1

Comments

Submitted by ryanzurrin on Mon, 04/12/2021 - 04:24

the length of the mirror is related to the height of a person by just being half of their height. Will this be true in all cases though?

OpenStax College Physics Solution, Chapter 25, Problem 1 (Problems & Exercises) (2:43)

Calculator Screenshots

Comments

Solutions for problems in chapter 25