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How much pressure is transmitted in the hydraulic system considered in Example 11.6? Express your answer in pascals and in atmospheres. Example 11.6 Consider the automobile hydraulic system shown in Figure 11.13. A force of 100 N is applied to the brake pedal, which acts on the cylinder—called the master—through a lever. A force of 500 N is exerted on the master cylinder. Pressure created in the master cylinder is transmitted to four so-called slave cylinders. The master cylinder has a diameter of 0.500 cm, and each slave cylinder has a diameter of 2.50 cm.
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$2.5\times 10^{7}\textrm{ Pa}$
$2.5\times 10^{7}\textrm{ Pa} \times \dfrac{1 \textrm{ atm}}{1.013\times 10^{5}\textrm{ N/m}^2} = 147\textrm{ atm}$
Note: I forgot to express the answer in atmospheres in the video, but it's shown here in the final answer.
Solution Video

# OpenStax College Physics Solution, Chapter 11, Problem 24 (Problems & Exercises) (1:07)

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This is College Physics Answers with Shaun Dychko. We need to find the pressure in this hydraulic break system. So we can find the pressure anywhere... you know, in the slave cylinders or in the master cylinder because the pressure is the same throughout— that's what Pascal's principle says— and so we'll consider the pressure created by the master cylinder because we have information about it. We know that 500 newtons ends up being applied to this master cylinder and the diameter is 0.500 centimeters which we convert to meters by noticing that the prefix 'centa' means times 10 to the minus 2. So pressure is force divided by that area and it's a circular cross-section here— this cylinder is circular— and so the area is π times its radius squared and its radius is half its diameter so I have written d over 2 here and squared and then this works out to 4 times the force divided by π times the diameter squared. That's 4 times 500 newtons divided by π times 0.500 times 10 to the minus 2 meters squared which is 2.5 times 10 to the 7 pascals.