^{−8}Ω·m, find the resistivity of the 11 Ω wire.

$9.7 \times 10^{-8} \Omega$

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This is College Physics Answers with Shaun Dychko. We have two wires, each with the same length and the same cross-sectional area and they have different resistances, three ohms and 11 ohms. We're given the resistivity of one of the wires and we have to find the resistivity of the other. So resistance of wire one will be the resistivity of the material that wire one is made of, multiplied by its length divided by its area. I did not put a subscript one on the length or area factors because we're told that those things are the same between the two wires. So resistance for wire two is going to be resistivity number two multiplied by length -- the same length and divided by the same area and so when we divide these resistances, we take resistance two and instead of dividing a fraction by a fraction I'm multiplying by the reciprocal of the denominator here, so multiplying by <i>A</i> over <i>rho one l</i>. The A's and l's cancel leaving us with <i>rho two</i> over <i>rho one</i>. So we solve for resistivity two by multiplying both sides by resistivity one and we get resistivity two is resistivity one times resistance two divided by resistance one. That is 2.65 times ten to the minus eight ohm meters, resistivity for material one, multiplied by 11 ohms resistance of the second wire divided by three ohm resistance of the first wire. This gives 9.7 times ten to the minus eight ohm meters for the resistivity of the second resistor.