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What are the possible values of $m_l$ for an electron in the $n = 4$ state?
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$m_l = -3, -2, -1, 0, 1, 2, 3$
Solution Video

OpenStax College Physics Solution, Chapter 30, Problem 37 (Problems & Exercises) (1:06)

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Video Transcript
This is College Physics Answers with Shaun Dychko. We are told that the principal quantum number for an electron around an atom is 4 and we are asked what are the possible values of the angular momentum projection quantum number, m l. Now, we don't know what l is because we are not told but we can choose a maximum l such that we get the maximum number of possibilities for m l because m l is possibilities are constrained by whatever the value of l is. And so the maximum possible l is 3 because it follows the sequence starting from 0, 1 to up to a maximum of principal quantum number minus 1 so that is 4 minus 1. So the maximum possible angular momentum quantum number is 3. So with that being 3, the angular momentum projection quantum number can start from negative 3 which is negative l and increasing by 1's to negative 2, negative 1, 0, 1, 2 or a maximum of l so a maximum of 3. So these are the possible values for m l given a principal quantum number of 4.