Question

Two objects of equal mass collide. Object A is initially moving in the +x-direction with a speed of 12 m/s, and object B is initially at rest. After the collision, object A is at rest, and object B is moving away with some unknown velocity. There are no external forces acting on the system of two masses. What statement can we make about this collision?

- Both momentum and kinetic energy are conserved.
- Momentum is conserved, but kinetic energy is not conserved.
- Neither momentum nor kinetic energy is conserved.
- More information is needed in order to determine which is conserved.

Final Answer

(a)

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This is College Physics Answers with Shaun Dychko.
Since no external forces are acting on the system we know for sure that momentum is conserved. So that means we can write down this first statement that

*mA vA*plus*mB vB*the total momentum before the collision, equals*mA vA prime*plus*mB vB prime*, the total momentum after the collision. Now, we can factor out the m because we're told the objects are of equal mass, so*mA*and*mB*are the actually the same factor and we can cancel it everywhere. So we get*vA*plus*vB*equals*vA prime*plus*vB prime*. Let's solve this for*vB prime*to see what this unknown velocity is, and we'll subtract*vA prime*from both sides. We get*vB prime*equals*vA*plus*vB*minus*vA prime*. So*vA*is the 12 meters per second initial velocity of object A and*vB*we're told is initially at rest and so it's zero. Then we're told after the collision object A which is*vA prime*, its velocity will be zero. So this works out to 12 meters per second. So the object B after the collision has a velocity of 12. Now, then we can turn our attention to the conservation of energy formula to see if it is true that the total kinetic energy before the collision is the same as the total kinetic energy after the collision. Now, the*vB*term here is zero because object B has no velocity initially and this term also is zero because object A has no velocity initially. We can multiply everything by two and divide everything by this common mass, there is no need to put a subscript there because mass A and B are the same. So what we're left with is*vA*squared equals vB prime squared. Now if this is true, then kinetic energy is also conserved. It is true because*vA*is 12 meters per second and 12 squared equals*vB prime*squared which also is 12. So we can say A, both momentum and kinetic energy are conserved.