Question

(a)
This is College Physics Answers with Shaun Dychko. This force represents friction going up the hill opposing the velocity of the toboggan. Here's the normal force exerted by the hill and gravity is straight down, and a component of that gravity is along the slope. This component here combined with this push force, these two together will be added and they will look like they exceed the friction. We expect the answer to be A to this question, the acceleration down the hill.
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