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Question
Suppose a man stands in front of a mirror as shown in Figure 25.49. His eyes are 1.65 m above the floor, and the top of his head is 0.13 m higher. Find the height above the floor of the top and bottom of the smallest mirror in which he can see both the top of his head and his feet. How is this distance related to the man’s height?
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$h_\textrm{b} = 0.825 \textrm{ m}$
$h_\textrm{t} = 1.72 \textrm{ m}$
Note: The man's height affects the answer: the height of the bottom of the mirror is half the distance from the man's eyes and the ground, whereas the top of the mirror height is the height of the man's eyes plus half the distance between the man's eyes and top of his head.
Solution Video

# OpenStax College Physics for AP® Courses Solution, Chapter 25, Problem 1 (Problems & Exercises) (2:43)

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