Change the chapter
Question
The power of a physician’s eyes is 53.0 D while examining a patient. How far from her eyes is the feature being examined?
Question by OpenStax is licensed under CC BY 4.0.
33.3 cm
Solution Video

OpenStax College Physics for AP® Courses Solution, Chapter 26, Problem 13 (Problems & Exercises) (0:59)

Sign up to view this solution video!

Rating

No votes have been submitted yet.

Quiz Mode

Why is this button here? Quiz Mode is a chance to try solving the problem first on your own before viewing the solution. One of the following will probably happen:

  1. You get the answer. Congratulations! It feels good! There might still be more to learn, and you might enjoy comparing your problem solving approach to the best practices demonstrated in the solution video.
  2. You don't get the answer. This is OK! In fact it's awesome, despite the difficult feelings you might have about it. When you don't get the answer, your mind is ready for learning. Think about how much you really want the solution! Your mind will gobble it up when it sees it. Attempting the problem is like trying to assemble the pieces of a puzzle. If you don't get the answer, the gaps in the puzzle are questions that are ready and searching to be filled. This is an active process, where your mind is turned on - learning will happen!
If you wish to show the answer immediately without having to click "Reveal Answer", you may . Quiz Mode is disabled by default, but you can check the Enable Quiz Mode checkbox when editing your profile to re-enable it any time you want. College Physics Answers cares a lot about academic integrity. Quiz Mode is encouragement to use the solutions in a way that is most beneficial for your learning.

Video Transcript
This is College Physics Answers with Shaun Dychko. The power of this physician's eye is the reciprocal of object distance plus the reciprocal of object distance. The image distance is the lens retina distance which we're told is two centimeters. And, the power we're told is 53 diopters. And so, we're going to be solving for object distance. And, we'll do that by subtracting one over image distance from both sides and then switch the sides around and we get one over the object distance is power minus one over the image distance. Then, we'll take both sides to the power of negative one, and on the left we take the reciprocal solving for object distance, which is the distance between the lens and the object being observed. And then on the right side, we'll just leave it as it is to the power of negative one. So, that's 54 diopters minus one over two centimeters written as times ten to the minus two meters and all to the negative one, giving us 0.3333 meters, which is 33.3 centimeters.