Look up the values of the quantities in aB=h24π2mekqe2a_B = \dfrac{h^2}{4\pi^2m_ekq_e^2}, and verify that the Bohr radius aBa_B is 0.529×1010 m0.529\times 10^{-10}\textrm{ m}.
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OpenStax College Physics for AP® Courses, Chapter 30, Problem 9 (Problems & Exercises)

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This is College Physics Answers with Shaun Dychko. The Bohr radius is Planck's constant squared divided by 4 times π squared times the mass of an electron times Coulomb's constant times the elementary charge squared. So we substitute for each of these constants and then get our answer; 5.29 times 10 to the minus 11 meters is the Bohr radius.