Question
$^{241}_{95}\textrm{Am}$ is commonly used in smoke detectors because its $\alpha$ decay process provides a useful tool for detecting the presence of smoke particles. When $^{241}_{95}\textrm{Am}$ undergoes $\alpha$ decay, what is the resulting nucleus? If $^{241}_{95}\textrm{Am}$ were to undergo $\beta$ decay, what would be the resulting nucleus? Explain each answer.