WEBVTT
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This is College Physics Answers
with Shaun Dychko
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We consider the path A in this question.
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And part A asks,
‘What is the distance traveled?‘
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And so, that's the total
length of the path taken
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from the start to the end point.
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And for Part A,
it's a bit of a simpler question
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because since there aren't any...
isn't any backtracking,
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the distance traveled is going to be the
same as the magnitude of the displacement.
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So, there are 7 units here of distance
between the start and end point.
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We’ll assume that this lines up midway
between the 6 and the 8 meters,
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which makes this 7.
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And, the distance traveled, 7 meters.
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And the magnitude of the displacement
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is the size of the
number of the displacement.
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Well, let's do Part C first actually,
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and find that displacement
and then take the magnitude of it.
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So, Part C says the... well,
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displacement is the final position
minus the initial position.
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And that's going to be 7 meters
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- the final position minus
the initial position of zero.
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And that gives 7 meters.
It is the displacement.
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And we put a plus sign here,
which we don't actually have to,
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but we do it anyway just to emphasize
that this is a positive 7 meters,
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to emphasize that this is a
displacement in the positive direction.
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Now, the magnitude of this number
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or the absolute value of it
in other words is 7 meters.
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So, it's really not that special.
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Magnitude means you just take
the number part and ignore the sign.
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So, if this was a negative 7 meters,
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then the absolute value,
or the magnitude of it in other words,
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would still also be 7.
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Okay. So, there we have it.